{"id":2620,"date":"2026-09-23T12:07:01","date_gmt":"2026-09-23T12:07:01","guid":{"rendered":"https:\/\/nhdbio.com\/?p=2620"},"modified":"2026-10-11T07:37:52","modified_gmt":"2026-10-11T07:37:52","slug":"%e3%83%9a%e3%83%97%e3%83%81%e3%83%89%e3%81%ae%e9%80%a3%e7%b6%9a%e5%b8%8c%e9%87%88%e5%90%b8%e7%9d%80%e3%82%a2%e3%83%83%e3%82%bb%e3%82%a4%e6%9b%b2%e7%b7%9a","status":"publish","type":"post","link":"https:\/\/nhdbio.com\/ja\/peptide-serial-dilution-adsorption-assay-curves\/","title":{"rendered":"\u9023\u7d9a\u30da\u30d7\u30c1\u30c9\u5e0c\u91c8\uff1a\u5404\u30c1\u30e5\u30fc\u30d6\u3068\u30d7\u30ec\u30fc\u30c8\u4f4d\u7f6e\u306b\u5f93\u3063\u3066\u304f\u3060\u3055\u3044"},"content":{"rendered":"

A row of tubes labeled 100, 50 and 25 \u00b5M looks straightforward. The difficulty is remembering which solution moves where, and how much remains. We will follow one twofold dilution series from the first tube to the plate.<\/p>\n

\u306a\u305c\u7b49\u91cf\u3067\u6fc3\u5ea6\u304c\u534a\u5206\u306b\u306a\u308b\u306e\u304b<\/h2>\n

Start with 100 \u00b5L at 100 \u00b5M and add 100 \u00b5L of suitable diluent. The final volume is 200 \u00b5L. If no material is lost, the amount of peptide stays the same while the volume doubles, so the concentration becomes 50 \u00b5M.<\/p>\n

100 \u00b5M \u00d7 100 \u00b5L \u00f7 200 \u00b5L = 50 \u00b5M<\/p>\n

\"Figure
\u56f3 1\u3002\u6eb6\u6db2\u3068\u5e0c\u91c8\u6db2\u3092\u7b49\u91cf\u306b\u3059\u308b\u30682\u500d\u5e0c\u91c8\u306b\u306a\u308a\u307e\u3059\u3002<\/figcaption><\/figure>\n

\u6b21\u306e4\u672c\u306e\u8a66\u9a13\u7ba1\u3092\u8ffd\u3046<\/h2>\n

Keep enough 100 \u00b5M solution in tube 1. Put 100 \u00b5L of diluent in each of tubes 2\u20135. Transfer 100 \u00b5L from tube 1 into tube 2 and mix; then transfer 100 \u00b5L from tube 2 into tube 3 and mix. Continue in that order.<\/p>\n

The concentrations are 100, 50, 25, 12.5 and 6.25 \u00b5M. Mix before taking the aliquot for the next tube, so the transferred liquid represents the newly diluted solution.<\/p>\n

\"Figure
\u56f3 2\u3002\u5404\u6bb5\u968e\u306e\u79fb\u3057\u66ff\u3048\u3067\u3001\u6b21\u306e\u6eb6\u6db2\u306e\u6fc3\u5ea6\u306f\u534a\u5206\u306b\u306a\u308a\u307e\u3059\u3002<\/figcaption><\/figure>\n

\u5404\u30c1\u30e5\u30fc\u30d6\u306b\u6b8b\u3063\u3066\u3044\u308b\u6db2\u4f53\u3092\u6570\u3048\u308b<\/h2>\n

Tube 2 contains 200 \u00b5L after mixing, but only 100 \u00b5L after you transfer half to tube 3. The same applies to the later transfer tubes. The final tube remains at 200 \u00b5L if you do not remove an aliquot.<\/p>\n

That difference matters when you plan how many wells each tube can fill. The first tube\u2019s remaining volume also depends on how much starting stock you prepared.<\/p>\n

\u4f7f\u7528\u6db2\u306f\u30a6\u30a7\u30eb\u5185\u3067\u3055\u3089\u306b\u5e0c\u91c8\u3055\u308c\u308b\u3053\u3068\u304c\u3042\u308a\u307e\u3059<\/h2>\n

If a 50 \u00b5M working solution is mixed with an equal volume of another solution containing no peptide, the final concentration is 25 \u00b5M. The concentration on the tube is not automatically the concentration in the well.<\/p>\n

\u6fc3\u5ea6\u3001\u53cd\u5fa9\u3001\u5bfe\u7167\u30a6\u30a7\u30eb\u3092\u793a\u3059\u30d7\u30ec\u30fc\u30c8\u30de\u30c3\u30d7\u3092\u63cf\u304d\u307e\u3059\u3002\u3053\u308c\u306b\u3088\u308a\u3001\u5e0c\u91c8\u8a08\u7b97\u304c\u5b9f\u969b\u306e\u30ec\u30a4\u30a2\u30a6\u30c8\u3068\u7d50\u3073\u3064\u304d\u307e\u3059\u3002<\/p>\n

\"\u56f33\u3002\u6559\u80b2\u7528\u30d7\u30ec\u30fc\u30c8\u30de\u30c3\u30d7\u3067\u306f\u6fc3\u5ea6\u3001\u53cd\u5fa9\u3001\u5bfe\u7167\u3092\u5225\u3005\u306b\u4fdd\u3061\u307e\u3059\u3002\"
\u56f3 3\u3002\u30d7\u30ec\u30fc\u30c8\u30de\u30c3\u30d7\u306f\u3001\u5e0c\u91c8\u30b9\u30c6\u30c3\u30d7\u3001\u53cd\u5fa9\u3001\u5bfe\u7167\u3092\u307e\u3068\u3081\u3066\u628a\u63e1\u3059\u308b\u306e\u306b\u5f79\u7acb\u3061\u307e\u3059\u3002<\/figcaption><\/figure>\n

\u3082\u3046\u4e00\u5ea6\u624b\u9806\u3092\u78ba\u8a8d\u3059\u308b<\/h2>\n
Mix 80 \u00b5L of a 25 \u00b5M solution with 80 \u00b5L of diluent. What concentration results?<\/strong><\/p>\n
\n\u7b54\u3048\u3092\u898b\u308b<\/summary>\n

12.5 \u00b5M. The final volume is 160 \u00b5L. If you then remove 80 \u00b5L, the remaining solution is still 12.5 \u00b5M, but only 80 \u00b5L remains.<\/p>\n<\/details>\n<\/div>\n

\u3053\u306e\u8a08\u7b97\u306f\u3001\u30da\u30d7\u30c1\u30c9\u304c\u6eb6\u89e3\u3057\u305f\u307e\u307e\u3067\u5bb9\u5668\u306b\u5931\u308f\u308c\u306a\u3044\u3053\u3068\u3092\u524d\u63d0\u3068\u3057\u3066\u3044\u307e\u3059\u3002\u4f4e\u6fc3\u5ea6\u3067\u56de\u53ce\u7387\u304c\u91cd\u8981\u306a\u3089\u3001\u5225\u9014\u691c\u8a0e\u3057\u3066\u304f\u3060\u3055\u3044\u3002<\/p>\n

KPV \u307e\u305f\u306f LL-37 \u3092\u7528\u3044\u305f\u5e0c\u91c8\u8a08\u753b\u3092\u4f7f\u7528\u3059\u308b\u5834\u5408<\/h2>\n

KPV \u307e\u305f\u306f LL-37 \u306e\u5e0c\u91c8\u3092\u8a08\u753b\u3059\u308b\u969b\u306f\u3001\u958b\u59cb\u524d\u306b\u539f\u6db2\u6fc3\u5ea6\u3068\u6eb6\u5a92\u3092\u78ba\u8a8d\u3057\u3066\u304f\u3060\u3055\u3044\u3002\u5e0c\u91c8\u8868\u306f\u88fd\u54c1\u5f62\u614b\u304a\u3088\u3073\u30ed\u30c3\u30c8\u60c5\u5831\u3068\u4e00\u7dd2\u306b\u4fdd\u7ba1\u3057\u3001\u5f8c\u306e\u30d0\u30c3\u30c1\u3092\u540c\u3058\u8a08\u753b\u6761\u4ef6\u3067\u6bd4\u8f03\u3067\u304d\u308b\u3088\u3046\u306b\u3057\u3066\u304f\u3060\u3055\u3044\u3002<\/p>\n

LL-37<\/a> \/ KPV<\/a><\/p>\n

\u8cc7\u6750\u304a\u3088\u3073\u6587\u66f8\u306e\u8981\u4ef6\u306b\u3064\u3044\u3066NHD\u3068\u76f8\u8ac7\u3059\u308b<\/a> \u00b7 \u5206\u6790\u30ac\u30a4\u30c9\u3092\u7d9a\u3051\u308b<\/a><\/p>\n